InterviewSolution
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InterviewSolution
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Unpolarized light falls on two polarizing sheets placed one on top of the other. What must be the angle between the characteristic directions of the sheets if the intensity of the transmitted light is one third of intensity of the inciddent beam? |
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Answer» Solution :Intensity of the light transmitted through the first polarizer `I_(1)= I_(0)"/"2`, where `I_0` is the intensity of the incident unpolarized light. Intensity of the light transmitted through the second polarizer is `I_(2)= I_(1) cos^(2) theta" where "theta` is the angle between the characteristic directions of the polarizer SHEETS. But `I_(2)= I_(0)"/"3` (given) `""THEREFORE I_(2)= I_(1)cos^(2)theta= (I_0)/(2)cos^(2) theta= (I_0)/(3)` `cos^(2) theta = 2"/"3 implies theta = cos^(-1) sqrt((2)/(3))`. |
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