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Up to what temperature has one to heat classiacal electronic gas to make the mean enrgy of its electrons equal to that of free electrons in copper at `T=0`? Only one free electron is supposed to correspond to each other atom. |
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Answer» The mean `K.E` of electrons in a Fermi gas is `(3)/(5)E_(F)`. This muat equal `(3)/(2)kT`. Thus `T=(2E_(F))/(5k)` we calculate, `E_(F)` first. For `C_(u)` `n=(N_(A))/(M//rho)=(rhoN_(A))/(M)= "8.442xx10^(22)per c.c` Then `E_(F)= 7.01eV` and `T= 3.25xx10^(4)K` |
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