1.

Upon expansion, the pressure of a gas rose linearly (Fig. ). What work did the gas perform? By how much did its internal energy increase? What quantity of heat has been supplied to it? The gas was monoatomic. What was the molar leat of the gas in this process? Compare with the specific heals al constant pressure and at constant volume.

Answer»


Solution :The work `W = 1/2(p_2 + p_1)(V_2 - V_1)`. The change in the internal energy is
`DeltaU = m/M C_(MV) (T_2 - T_1) = (C_(mv))/(R) (p_2V_2 - p_1V_1)`
The quantity of heat is `Q = DeltaU + A`.
The molar heat is
`C_m = Q/(T_2 - T_1) = (QR)/(p_2V_2 - p_1V_1)`
and its ratio to the GAS constant is
`(C_(m))/(R) = (Q)/(p_2V_2 - p_1V_1) = 2.06 `
The corresponding VALUE for a monoatomic gas is `C_(mp)//R = 2.5, C_(mv)//R = 1.5`. Clearly
`C_(mv) LE C_m le C_(mp)`.


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