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Upon fully dissolving 2.0 g of a metal in sulfuric acid, 6.8 g of the metal sulfate is formed. The equivalent weigth of the metal is-A. `13.6 g`B. `20.0g`C. `4.0g`D. `10.0g` |
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Answer» Correct Answer - B Equivalents of metal=Equivalents of metal sulphate `("wt.of metal")/("Eq. wt. of metal")("wt. of metal sulphate")/("Eq. wt. metal sulphate")` `(2)/(x)=(6.8)/(x +48)` `6.8x=2x+96` `4.8x=96` `x=(96)/(4.8)=20` |
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