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Use a suitable identity to find the product.(x+5)(x+5) |
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Answer» Answer: We know (x−5)(x−5)=(x−5)2Now using IDENTITY (x−y)2=x2−2xy+y2 We know (x−5)(x−5)=(x−5)2Now using identity (x−y)2=x2−2xy+y2Here x=x and y=5 We know (x−5)(x−5)=(x−5)2Now using identity (x−y)2=x2−2xy+y2Here x=x and y=5(x−5)2=(x)2−2×x×5+(5)2 We know (x−5)(x−5)=(x−5)2Now using identity (x−y)2=x2−2xy+y2Here x=x and y=5(x−5)2=(x)2−2×x×5+(5)2=x2−10x+25 |
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