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Use Bohr's model of hydrogen atom to obtain the relationship between the angular momentum and t magnetic moment of the revolving electron. |
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Answer» Solution :When an electron revolves around the nucleus in an HYDROGEN atom, an equivalent current `I= (ev)/(2pir)` is set up and the magnetic moment associated with the CIRCULATING current is equivalent to `vecmu_(l)=I.A=(ev)/(2pir)xxpir^(2)=(evr)/(2)` However, as PER Bohr.s quantum condition, the angular momentum of the revolving electron is an integer multiple of `(h)/(2pi) i.e` `|vecl |= mvr = (nh)/(2pi)` Comparing (i) and (II) we find that Comparing (i) and (ti), we find that `|vecmu_(l)|= (e)/(2M).|vecl|` |
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