1.

Use differentials to approximate the cube root of 127.

Answer» `y = f(x) = (x)^(1/2)`
`(127)^(1/3) = f(x + /_ x) `
when `x=125 & /_x=2`
`f(x+ /_ x) = /_ y + f(x) `
`f(x) = f(125) = (125)^(1/3) = 5`
`/_ y = dy = (dy/dx) /_/x`
`= d/dx(x^(1/3)) xx 2`
`= [1/(3x^(2/3))] xx 2`
`= 2/(3x^(2/3))`
`= 2/(3 xx25) = 2/75`
`/_ y = 0.027`
`f(x+ /_x ) = f(127) = (127)^(1/3) = 5 + 0.027= 5.027 `
Answer


Discussion

No Comment Found

Related InterviewSolutions