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The approximate value of `(1.0002)^3000`, isA. `1.2`B. `1.4`C. `1.6`D. `1.8` |
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Answer» Correct Answer - C Let `y=x^(3000), x=1 and x+Delta x = 1.0002` Then, `Delta x=1.0002-1=0.0002` Also,y=1 when x=1 Now, `y=x^(3000)` `rArr" "(dy)/dx=3000" "x^(2999) rArr((dy)/dx)_(x=1)=3000` `:." "Deltay=(dy)/dxDeltax` `rArr" "Deltay= 3000 xx0.0002 = 6/10=0.6` Hence `(1.0002)^(3000)= y+Deltay=1+0.6=1.6` |
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