InterviewSolution
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Find df for f(x) = x2 + 3x and evaluate it for (i) x = 2 and dx = 0.1 (ii) x = 3 and dx = 0.02 |
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Answer» y = f(x) = x + 3x dy = (2x + 3) dx (i) dy {when x = 2 and ate = 0.1} = [2(2) + 3] (0.1) = 7(0.1) = 0.7 (ii) dy {when x = 3 and dx = 0.02} = [2(3) + 3] (0.0.2) = 9(0.02) = 0.18 |
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