1.

Find df for f(x) = x2 + 3x and evaluate it for (i) x = 2 and dx = 0.1 (ii) x = 3 and dx = 0.02

Answer»

y = f(x) = x + 3x 

dy = (2x + 3) dx 

(i) dy {when x = 2 and ate = 0.1} 

= [2(2) + 3] (0.1) 

= 7(0.1) 

= 0.7

(ii) dy {when x = 3 and dx = 0.02} 

= [2(3) + 3] (0.0.2) 

= 9(0.02) 

= 0.18



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