Use identity to factorise a² + c² - b² + 2ac

1.	Use identity to factorise a² + c² - b² + 2ac
Answer» a^2–2ab+b^2 - c^2 ((a-b)(a-b))-c^2 (a-b)^2-c^2 Set X =a-b and y=c. The formula becomes x^2-y^2 factoring this polynomial, we get (x+y)(x-y) SUBSTITUTING back, we get: (a-b+c)(a-b-c) Let’s multiply it out to check: A^2 -ab ac - ab B^2 -bc -ac bc -c^2 / QED. Break it down into parts: a²+b²-2ab=(a-b)(a-b) a²+b²-c²-2ab=(a-b)²-c² Then, FACTOR in c²: (a-b)²-c²=((a-b)+c)((a-b)-c) =(a-b+c)(a-b+c)..... HOPE IT HELPS UH

Answer»

a^2–2ab+b^2 - c^2

((a-b)(a-b))-c^2

(a-b)^2-c^2

Set X =a-b and y=c. The formula becomes

x^2-y^2

factoring this polynomial, we get

(x+y)(x-y)

SUBSTITUTING back, we get:

(a-b+c)(a-b-c)

Let’s multiply it out to check:

A^2 -ab ac

- ab B^2 -bc

-ac bc -c^2

/ QED.

Break it down into parts:

a²+b²-2ab=(a-b)(a-b)

a²+b²-c²-2ab=(a-b)²-c²

Then, FACTOR in c²:

(a-b)²-c²=((a-b)+c)((a-b)-c)

=(a-b+c)(a-b+c).....

HOPE IT HELPS UH