Saved Bookmarks
| 1. |
Use Kirchhoff's rules to determine the potential difference between the points A and D when no current flows in the arm BE of the electric network shown in the Fig. |
|
Answer» Solution : As per question no current flows in the ARM BE of ELECTRIC CIRCUIT, so a constant current I flows along AFEDCBA as shown in above FIG. Now applying Kirchhoff.s loop rule for AFEBA, we have -2I +1 -3I +3 +6=0`rArr 5I = 10 `or I = 2 A Now considering the path AFED, we have `V_A - 2I + 1 - 3I = V_D rArr V_A - V_D = 5I - 1 = 5 xx 2 - 1 = 10 - 1 = 9 V` |
|