Use the following standard electrode potentials, calculate `DeltaG^(@)` in kJ`//`mol for the indicated reaction : `5Ce^(4+)(aq)+Mn^(2+)(aq)+4H_(2)O(l)to5Ce^(3+)(aq)+MnO_(4)^(-)(aq)+8H^(+)(aq)` `MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-)toMn^(2+)(aq)+4H_(2)O(l), E^(@)=+1.51 V` `Ce^(4+)(aq)+e^(=)toCe^(3+)(aq)" "E^(@)=+1.61 V`A. `-9.65`B. `-24.3`C. `-48.25`D. `-35.2`

Use the following standard electrode potentials, calculate `DeltaG^(@)

1.	Use the following standard electrode potentials, calculate `DeltaG^(@)` in kJ`//`mol for the indicated reaction : `5Ce^(4+)(aq)+Mn^(2+)(aq)+4H_(2)O(l)to5Ce^(3+)(aq)+MnO_(4)^(-)(aq)+8H^(+)(aq)` `MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-)toMn^(2+)(aq)+4H_(2)O(l), E^(@)=+1.51 V` `Ce^(4+)(aq)+e^(=)toCe^(3+)(aq)" "E^(@)=+1.61 V`A. `-9.65`B. `-24.3`C. `-48.25`D. `-35.2`
Answer» Correct Answer - C `E_(cell)^(@)=E_(RP(RHS))^(@)-E_(RP(LHS))^(@)` `=1.61-1.51rArr0.10V` `DeltaG^(@)=-nFE^(@)rArr-5xx96500xx0.10J` `DeltaG^(@)=-48.25kJ`

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