1.

Use the given data to calculate the resonance energy of N_(2)O.(Delta_(f)H^(ө) of N_(2)O=82kJmol^(-1)) Bond energy of N=Oto607kJmol^(-1) Bond energy of O=Oto498kJmol^(-1) bond energy of N=Nto418kJmol^(-1) Bond energy of N-=Nto946kJmol^(-1) Choose the correct option.

Answer»

82 KJ `mol^(-1)`
`-88kJ` `mol^(-1)`
`-82` kJ `mol^(-1)`
`+88kJmol^(-1)`

SOLUTION :`N-=N(g)+(1)/(2)O_(2)(g) to N=N=O`
Calculated VALUE of
`Delta_(f)H^(ө)H^(a(s)toNa(g),Delta_(g)H^(ө)=[BE(N-=N)+(1)/(2)BE(O=O)]`
`-[BE(N=N)+BE(N-=overset(+)(O))]`
`=[946+(1)/(2)(498)]-[418+607]`
`=170" kJ "mol^(-1)`
Resonance energy=Observed `Delta_(f)H^(@)-`Calculated `Delta_(f)H^(@)`
`=82-170=88" kJ "mol^(-1)`.


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