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Use the given standard enthalpies of formation (in kJ/mol) to determine the enthalpy of reaction of the following reaction : `NH_(3)(g)+3F_(2)(g)rarrNF_(3)+3HF(g)` `DeltaH_(f)^(@)(NH_(3),g)=-46.2, " "DeltaH_(f)^(@)(NF_(3),g)=-113.0 ," "DeltaH_(f)^(@)(HF, g)=-269.0`A. `-335.8 kJ//mol`B. `-873.8 kJ//mol`C. `-697.2 kJ//mol`D. `-890.4 kJ//mol` |
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Answer» Correct Answer - B `Delta_(r )H=(Delta_(f)H)_(P)-(Delta_(f)H)_(R)` `Delta_(r )H=-113 + 3xx(-269)+46.2 =-873.8 " kJ"` |
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