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Use the mirror equation to deduce that a.An object placed between f and 2f of a concave mirror produces a real image beyond 2f. |
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Answer» Solution :a.`(1)/(u) + (1)/(v) = (1)/(f) , (1)/(V) = (1)/(f)- (1)/(u) `............... (1) f and u are negative . i.e, f `lt` 0 and `u lt 0` . Object is placed betweenf and 2f, then `2f lt u lt f or (1)/(2f) gt (1)/(u) gt (1)/(f) ` i.e., - `(1)/(2f) lt - (1)/(u) lt - (1)/(f) ` `(1)/(f) - (1)/(2f) lt (1)/(f) - (1)/(u) lt (1)/(f) - (1)/(f)` Using EQUATION (1) `RARR (1)/(2f) lt (1)/(v) lt 0 ` i.e., .v. is negative, the IMAGE FORMED is REAL and beyond 2f. |
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