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Use the same formula you employ in (a) to obtain electron speed for an collector potential of 10 MV. Do you see what is wrong ? In what way is the formula to be modified ? |
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Answer» V = 10 MV = `10^(7) V , v = sqrt(e/m xx2v)= sqrt(1.76 xx10^(11) xx 2 xx10^(7)) :. v = 1.8762 xx10^(9) ` m/s This speed is greater than speed of light , which is not possible . As `v` approaches to c, then mass m = ` (m_(0))/(sqrt(1-(v^(2))/(c^(2))))` |
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