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Using anylatical geometery prove that diagonals of rhombus are perpendicular to each other |
| Answer» LET A(x,0), B(0,y), C(−x,0) & D(0,−y) be the vertices of the rhombus.We can verify by distance formula that AB=BC−CD=DA= x 2 +y 2AC & BD are diagonals of rhombus which INTERSECT at 'O'.Now, AC & BD are ALONG x-axis & y-axis which are PERPENDICULAR to each other.Thus, diagonals of a rhombus are perpendicular to each other. | |