1.

Using binomial theorem, evaluate : `(96)^3`

Answer» `(96)^3=(100-4)^3`
`(x+a)^n=sum_(r=0)^(n).^nC_ra^rr^(n-r)`
`(100-4)^3= .^3C_0(100)^3+.^3C_1(100)^2(-4)^(1).+^3C_2(100)^1(-4)^(2)+.^3C_3(100)^0(-4)^(3)`
=>`1000000-120000+4800-64`
=>`884736`.


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