1.

Using Dulong and Petit's law, what will be the atomic mass of metal having specific heat capacity 0.1344 JK^(-1)gm^(-1)

Answer»

47.62 gm/mol
840 gm/mol
100 gm/mol
200 gm/mol

Solution :SPECIFIC heat (Cal/mole-K: atomic MASS `approx6.4`
`(0.1344)/(4.2)xx` atomic mass `approx6.4`
Atomic mass `APPROX=(6.4xx4.2)/(0.1344)=200 gm//"mol"`


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