Saved Bookmarks
| 1. |
Using elementary transformations, find the inverse of the matrix`[[2,-3],[-1, 2]]` |
|
Answer» Here, `A = [[2,-3],[-1,2]]` We know, `A = IA` `=>[[2,-3],[-1,2]]= [[1,0],[0,1]]A` Applying `R_1->R_1+R_2` `=>[[1,-1],[-1,2]] = [[1,1],[0,1]]A` Applying `R_2->R_1+R_2` `=>[[1,-1],[0,1]] = [[1,1],[1,2]]A` Applying `R_1->R_1+R_2` `=>[[1,0],[0,1]] = [[2,3],[1,2]]A` `=>I = [[-1,3],[-1/2,1]]A` Comparing it with , `I = A^-1A` So, `A^-1 = [[2,3],[1,2]]` |
|