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using euipartion of energy, the specific heat `("in" jkg^(-1)K^(-1)`of aluminium at room temperature can be estimated to be (atomic weigh of aluminium=27)A. `410`B. `925`C. `25`D. `1850` |
Answer» Correct Answer - B Energy `E = (nfRT)/(2) = (m)/(M_(0))(6RT)/(2) … (i)` (degree of freedom for Al = `6` , `M_(0)= "molecular mass of Al")` and `Q =msT`…..(ii) From (i) & (ii) `(3mRT)/(M_(0)) = msT` |
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