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Using `._(f)G^(Theta)(Hi) = 1.3 kJ mol^(-1)`, calculate the standard free enegry change for the following reaction: `H_(2)(g) +I_(2)(g) rarr 2HI(g)` |
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Answer» `DeltaG^(Theta) = sum_(f)G^(Theta) ("products") -sum_(f)G^(Theta)("reactants")` `= 2xx(1.3) -(0+0)` `= 2.6 -0 = 2.6 kJ mol^(-1)` |
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