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Using Kichhoff's law in the given circuit determine the voltange drop a cross the unknown resistor 'R' |
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Answer» Solution :Applying kirchhoff's second rule (law) in the closed loop ABFEA. `-0.5xx2=V_(A)-V_(B)-3` `-1+3=V_(A)-V_(B)` `V_(A)-V_(B)=2Va` POTENTIAL drop ACROSS R si 2V as R, EF & AB are parallel. |
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