1.

Using Kichhoff's law in the given circuit determine the voltange drop a cross the unknown resistor 'R'

Answer»

Solution :Applying kirchhoff's second rule (law) in the closed loop ABFEA.
`-0.5xx2=V_(A)-V_(B)-3`
`-1+3=V_(A)-V_(B)`
`V_(A)-V_(B)=2Va`
POTENTIAL drop ACROSS R si 2V as R, EF & AB are parallel.


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