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Using Kirchhoff's rules determine the value of unknown resistance R in the circuit so that no current flows through 4 Omega resistance. Also find the potential difference between A and D. |
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Answer» Solution :Apply Kirchoof.s Voltage rule For loop ABEA `-9 + 6 + 4 xx 0 + 2 I =0` `2I -3 =0` `I = 3/2 = 1. 5 A` For loop ABCED `3 + IR + 4 xx 0-6 =0` `THEREFORE IR =3` Substituting the value of current I, `3/2 xx R =3 ` `therefore R = 2Omega` Potential DIFFERENCE between A & D through path ABCD: `+ 9V - 3 V - IR = V _(AD)` `+ 9- 3 - 3/2 xx 2 = V _(AD)` ` implies V _(AD) =3 V` Alternatively, through path AFD `3/2 xx 2 = V _(AD)` `implies V _(AD) = 3 V` |
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