Saved Bookmarks
| 1. |
Using Kirchhoff's rules determine the value of unknown resistance R in the circuit so that no current flows through 4 Omegaresistance. Also find the potential difference between A and D. |
|
Answer» SOLUTION :As per question no current flows through 4 `Omega`RESISTANCE. Hence current in branch EB is zero and current flowing through branch EDCB is I. ` THEREFORE ` For mesh AFEBA, we have - 1.I - 1.I - 6 + 9 = 0 ` rarr I = 1.5 A` Now for mesh BEDCB, we have `6 - R XX 1.5 - 3 = 0rArr R = 2Omega` Moreover, potential difference`V_A - V_D =9- 3 -IR = 9 - 3-(1.5) xx (2) = 3 V` |
|