1.

Using stock notation, represent the following compounds: HAuCl4, TI2O, FeO, Fe2O3, CuI, CuO, MnO and MnO2.CompoundOxidation Number of MetalStock NotationHAuCI41 + x + 4 (– 1) = 01 + x – 4 = 0x – 3 = 0x = +3HAu (III) CI4

Answer»

First of all the oxidation number of each metallic element in its compound is calculated. 

Then these compounds are represented as stock notation:

CompoundOxidation Number of MetalStock Notation
TI2O2(x) + (– 2) = 0
2x – 2 = 0
2x = 2
x = \(\frac{2}{2}\) =+1		TI2(I)O2
FeOx + (-2) = 0
x - 2 = 0
x = +2		Fe(II)O
Fe2O32(x) + 3 (– 2) = 0
2x – 6 = 0
2x = 6
x = \(\frac{6}{2}\) = +3		Fe2(III)O3
CuIx + (– 1) = 0
x – 1 = 0
x = +1		Cu(I)I
CuOx + (– 2) = 0
x – 2 = 0
x = +2		Cu(II)O
MnOx + (– 2) = 0
x – 2 = 0
x = +2		Mn(II)O
MnO2x + 2(– 2) = 0
x – 4 = 0
x = + 4		Mn(IV)O2


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