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Using the calculated emf value of zinc and copper electrode, calculate the emf of the following cell at 25^(@)C. Zn(s)abs(Zn^(2+)(aq, 1M))abs(Cu^(2+)(aq, 1M))Cu(s) |
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Answer» Solution :`Zn_((s))abs(Zn_(AQ, 1M)^(2+))abs(Cu_(aq, 1M)^(2+))Cu_((s))` `E_(Zn//Zn^(2+))^(@)=0.76 V` `E_(CU^(2+)|Cu)^(@)=0.34V` `E_("Cell")^(@)=E_("ox")^(@)+E_("red")^(@)` `""=0.76+0.34` `E_("Cell")^(@)=1.10V` |
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