InterviewSolution
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InterviewSolution
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Using the data provided, calculate the bond energy `( kJ mol^(-1)) ` of a `C-=C` bond in `C_(2)H_(2)`. That eneergy is ( take the bond energy ofC-H bond as350 kJ `mol^(-1))``2C(s) + H_(2)(g) rarr C_(2)H_(2)(g)" " DeltaH = 225 kJ mol^(-1)` `2C(s) rarr 2C(g) " " DeltaH = 1410 kJ mol^(-1)` `H_(2)(g) rarr 2H(g)" " DeltaH = 330 kJ mol^(-1)`A. 1165B. 837C. 875D. 815 |
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Answer» Correct Answer - D (i) `2C(s) + H_(2)(g) rarr H-C-= C-H(g), DeltaH=225kJ mol^(-1)` (ii) `2C(s) rarr 2C(g) , DeltaH = 1410kJ mol^(-1)` (iii) `H_92)9g)rar 2H(g), DeltaH = 330 kJ mol^(-1)` From eq. (i) `225= [2 xxDelta_(C(s) rarr C(g)) + BE_(H-H)]-[2BE_(C-H)+BE(C-=C)]` or `225=[ 1410 + 330]-[2 xx 350 k+ BE_(C-=C)]` or ` 225=1740- 700- BE_(C-=C)` or`BE_(C-=C) 1040-225 = 815kJ mol^(-1)` |
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