InterviewSolution
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InterviewSolution
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Using the data provided, calculate the multiple bond energy `(kJ mol^(-1))` of a `C-=C` bond in `C_(2)H_(2)`. That energy is `(` take the bond energy of a `X-H` bond as `350kJ mol^(-1))`. `2C_((s))+H_(2(g))rarr C_(2)H_(2(g)), Delta=225kJ mol^(-1)` `2C_((g))rarr 2C_(g)), DeltaH=1410kJ mol^(-1)` `H_(2(g)) rarr 2H_((g)),DeltaH=330kJ mol^(-1)`A. 1165B. 837C. 865D. 815 |
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Answer» Correct Answer - D Ethyne molecule breaks as `C_(2)H_(2(g))rarr 2C_((g))+2H_((g)) ….(i)` Given equations are `2C_((s))+H_(2(g))rarr H-C-=C-H_((g)) , DeltaH=225kJ mol^(-1) ....(ii)` `2C_((s)) rarr 2C_((g)), DeltaH=1410kJ mol^(-1) ...(iii)` `H_(2(g))rarr 2H_((g)), DeltaH=330kJ mol^(-1) ...(iv)` `:. 225=2xxDeltaH_(su b)C_((s))+B.E._((H_(2)))-2B.E._(C-H)-1xxB.E._(c-=C)` `225=2xx705+330-2xx350-B.E._(C-=C)` `225=1410+330-700-B.E._(C-=C)` `:. B.E._(C-=C)=815kJ mol^(-1)` |
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