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Using the Gibbs energy change, `Delta G^(@)=+ 63.3 kJ`, for the following reaction, `Ag_(2)CO_(3)hArr2Ag^(+)(aq)+CO_(3)^(2-)` the `K_(sp)` of `Ag_(2)CO_(3)(s)` in water at `25^(@)C` is `(R=8.314 JK^(-1)mol^(-1))`A. `3.2xx10^(-26)`B. `8.0xx10^(-12)`C. `2.9xx10^(-3)`D. `7.9xx10^(-2)` |
Answer» Correct Answer - B `DeltaG^@` is related to `K_sp` by the equation. `DeltaG^@=-2.303"RT log "K_sp` Given, `Deltag^@=+63.3kJ` `=63.3xx10^3J` Thus, substance `DletaG^@=63.3xx10^3J`. `R=8.314JK^(-1)mol^(-1)` and `T=298K[25+273K]` from the above equation we get, `63.3xx10^3=--2.303xx8.314xx298logK_sp` `therefore" "log K_sp=-11.09` `rArrK_sp ="anti log "(-11.09)` `K_sp=8.0xx10^(-12)` |
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