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Using the laws of conservation of energy and momentum |
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Answer» Solution :APPLYING laws of conservation of energy and momentum, we obtain `mgDeltay=(mv_x^2)/2+(mv_y^2)/2+(MV^2)/2-MV=mv_x` Noting that `DELTAY =ayt^2//2,Deltax=a_xt^2//2,Deltax = bt^2//2,v_x=a_xt,v_y =a_yt and V = bt` and that `Deltay = (Deltax - DeltaX)`TAN `alpha`we obtain after some simple transformations `a_x=(M gsinalphacos alpha)/(M+m sin^2alpha)` i.e. the same result as in PROBLEM 3.7. The value of a, is obtained from these equations in a similar way. The reaction is obtained from the CONDITION `Q=ma=msqrt(a_x^2+a_y^2)` |
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