InterviewSolution
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Using the prime factor method, find the H.C.F. of:(i) 5 and 8(ii) 24 and 49(iii) 40, 60 and 80(iv) 48, 84 and 88(v) 12, 16 and 28 |
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Answer» (i) Prime factor of 5 = 5 Prime factor of 8 = 2 x 2 x 2 No common prime factor H.C.F. of 5 and 8 = 1 (as both the number are co-prime) (ii) Prime factor of 24 = 2 x 2 x 2 x 3 Prime factor of 49 = 7 x 7 No common prime factor, number are co-prime. H.C.F. of 24 and 49 = 1. (iii) Prime factor of 40 = 2 x 2 x 2 x 5 Prime factor of 60 = 2 x 2 x 3 x 5 Prime factor of 80 = 2 x 2 x 2 x 2 x 5 Common prime factor = 2 x 2 x 5 H.C.F. of 40, 60 and 80 = 2 x 2 x 5 = 20 (iv) Prime factor of 48 = 2 x 2 x 2 x 2 x 3 Prime factor of 84 = 2 x 2 x 3 x 7 Prime factor of 88 = 2 x 2 x 2 x 11 Common prime factor of 48, 84 and 88 = 2 x 2 H.C.F. of 48, 84 and 88 = 2 x 2 = 4 (v) Prime factor of 12 = 2 x 2 x 3 Prime factor of 16 = 2 x 2 x 2 x 2 Prime factor of 28 = 2 x 2 x 7 Common prime factor between 12, 16 and 28 = 2 x 2 H.C.F. of 12, 16 and 28 = 2 x 2 = 4 |
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