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InterviewSolution
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Using the valence bond approach, deduce the shape and magnetic character of [Co(NH_(3))_(6)]^(3+). [Atomic number of Co = 27] |
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Answer» Solution :Electronic configuration of Co : [AR) `4s^(2) 3d^(7)`. Electronic configuration of Co3+ : [Ar) `4s^(0) 3d^(6)`. `NH_(3)` is a STRONG field ligand, it will cause pairing of electrons. Hence,  It has OCTAHEDRAL shape and is diamagnetic due to the ABSENCE of unpaired electrons. |
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