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Using valence bond theory explain geometry, hybridisation and magnetic property of [CoF_6]_3^- (Atomic number of Co = 27). |
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Answer» Solution :In this complex, the oxidation state of Co is +3. The electronic configuration ofcobalt in +3 oxidation state is `[Ar]3d^(6) 4s^(0)`. Orbitals of `Co^(3+)` ion are represented as  Since `F^(-)` ion provides a WEAK ligand field, one 4s, three 4p and TWO OUTER 4d-orbitals hybridised to yield six sp.d hybrid orbitals pointing towards the six corners of an octahedron.  These six hybridised orbitals of `Co^(3+)` overlaps with orbitals of six `F^(-)`ligands and six pairs of electrons donated by six F-to form six coordinate bonds.  Six `sp^(3)d^(2)` hybrid orbitals with six pairs of electrons from ligands. Thus, the complex has octahedral geometry. This complex is paramagnetic becauseof the presence of unpaired electrons,. |
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