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Utfind the complete solutio1n of P²+q²=4 |
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Answer» Answer: sinA=psinB−−−(1);cosA=qcosB−−−(2) tanA= q p
tanB−−−(3)(DIVIDING(1)by(2))sinAcosA=pqsinBcosB(Multiply(1)&(2)) cos 2 Acos 2 B sinAcosA
= cos 2 Acos 2 B pqsinBcosB
P²+q²=4 |
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