1.

UV radiations of 6.2 eV fall on an aluminium surface whose work function is 4.2 eV. The kinetic energy of the fastest electron emitted by the sluminium surface will be

Answer»

`3.2xx10^(-19)J`
`3.2xx10^(-21)J`
`3.2xx10^(-17)J`
`3.2xx10^(-34)J`.

Solution :`K_(MAX)=E-phi_(0)=(6.2-4.2)eV=2.0eV=2.0xx1.6xx10^(-19)J=3.2xx10^(-19)J`


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