1.

v_(e )and v_(p) denote the escape velocities from the earth and another planet having twice the radius and the same mean density as that of the earth. Then

Answer»

`v_(e )v_(p)//2`
`v_(e )=v_(p)`
`v_(e )=2v_(p)`
`v_(e )=(p)/(4)`.

SOLUTION :ESCAPE velocity `v_(e )=sqrt((2GM)/(R ))`
`=sqrt((2G)/(R )xx((4)/(3)piR^(3))rho)=sqrt((8piGrho)/(3))R`.
`:. (v_(e ))/(v_(p))=(R )/(2R )=(1)/(2)`.


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