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V V V3 3.3Find the shortest distance from the origin to the hyperbola x + 8 xy + 7y2 = 225.be the distance of thefrom​

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Answer:

Substituting in hyperbola we GET 45x2=225. So that x2=5 and SINCE y2=4x2 we get y2=20. Hence x2+y2=25. Thus required shortest distance is 5.

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