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Value of `(3+cot80^0cot20^0)/(cot80^0+cot20^0)`is equal toA. `cot20^(@)`B. `tan 50^(@)`C. `cot50^(@)`D. `cotsqrt(20^(@))` |
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Answer» Correct Answer - B `([3+(cos 80^(@)cos20^(@))/(sin80^(@)sin20^(@))])/([(cos 80^(@))/(sin80^(@))+(cos20^(@))/(sin20^(@))])` `=([2sin80^(@)sin20^(@)+(cos 80^(@)cos20^(@)sin80^(@)sin20^(@))])/(sin20^(@)cos80^(@)+cos20^(@)sin80^(@))` |
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