1.

Value of g on the surface of earth is `9.8 m//s^(2)`. Find its value on the surface of a planet whose mass and radius both are two times that of earth.

Answer» Correct Answer - B::D
`g = (GM)/(R^(2))` or `g prop (M)/(R^(2))`
Mass and radius both are two times. Therefore, value of g is half.


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