1.

Values of the acceleration `A` of a particle moving in simple harmonic motion as a function of its displacement `x` are given in the table below. `|{:(A(mm s^(-2)),16,8,0,-8,-16),(x(mm),-4,-2,0,2,4):}|` The pariod of the motion isA. `1/(pi)s`B. `(2)/(pi)s`C. `(pi)/(2)s`D. `pis`

Answer» Correct Answer - D
In SHM `a = -omega^(2)x`. So `16 = -omega^(2) (-4) rArr omega = 2 rArr "Time period" T = (2pi)/(omega) = (2pi)/(2) = pis`


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