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van der Waals constant b of helium is 24 mL `mol^(-1)`. Find molecular diameter of helium.A. `1.335 xx 10^(-10)cm`B. `1.335 xx 10^(-8)cm`C. `2.67 xx 10^(-8)cm`D. `4.34 xx 10^(-8)cm` |
Answer» Correct Answer - C `b = 4 xx` volume occuoied by molecules of `1mol` of a gas. or `b = 4N_(A) ((4)/(3)pir^(3))` or `r = ((3b)/(16N_(A^(pi))))^(1//3)` `= [(3xx24)/(16xx6.023 xx 10^(23)xx3.14)]^(1//3)cm` `= 1.355 xx 10^(-8)cm` Now, molecular diameter, `d = 2r = 2.67 xx 10^(-8)cm` |
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