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van der Waals constant b of helium is 24 mL `mol^(-1)`. Find molecular diameter of helium.A. `1.335xx10^(-10)"cm" `B. `1.335xx10^(-8)"cm" `C. `2.67xx10^(-8)"cm" `D. `4.34xx10^(-8)"cm" ` |
Answer» Correct Answer - c (c) b=4`xx`volume occupied by molecules of 1 mol of a gas, `or" "b=4N_(A)((4)/(3)pir^(3))` `or" " r=((3b)/(16N_(A)pi))` `=[(3xx24)/(16xx6.023xx10^(23)xx3.14)]^(1//3)" cm" ` `=1.355xx10^(-8) "cm" ` Now molecular diameter, d =2r `=2.67xx10^(-8)"cm"` |
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