Saved Bookmarks
| 1. |
Van't hoff factor for a dilute aqueous solution of hcn is 1.00002 .the percent degree of dissociation of the acid is |
|
Answer» DEGREE of DISSOCIATION (a) = I -1/n-1 a = 1.00002 - 1/2-1 a = 0.0002 |
|