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Vapour pressure of `C CL_(4)` at `25^@C` is `143` mmHg 0.05g of a non-volatile solute (mol.wt.=`65`)is dissolved in `100ml C CL_(4)`. find the vapour pressure of the solution (density of `C CL_(4)=158g//cm^2`)A. 94.39mmB. 141.93mmC. 134.44mmD. 199.34mm |
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Answer» Correct Answer - B Relative lowering in vapour pressure, `(p^(@)-p_(s))/(p_(@))=(wxxM)/(mxxW)` `(143-p_(s))/(143)=(0.5)/(65)xx(154)/(1.58xx100)" "[because"molecular weight of "C Cl_(4)=154 " and weight = density " xx" volume"]` `143-p_(s)=1.07rArrp_(s)=141.93mm` |
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