1.

Variance of the data 2,4,6,8,10 isA. 6B. 7C. 8D. None of these

Answer» Correct Answer - C
Here, `overline(x)=(2+4+6+8+10)/(5)=6`
Hence, variance `=(1)/(n) sum (x_(i)-overline(x))^(2)`
`=(1)/(5){(2-6)^(2)+(4-6)^(2)+(6-6)+(8-6)^(2)+(10-6)^(2)}`
`=(1)/(5){(16+4+0+4+16)}=(1)/(5){40}=8`


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