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Variation of `log_(10)K` with `(1)/(T)` is shown by the following graph in which straight line is at `45^(@)` , hence `Delta H^(@)` is: A. `+4.606cal`B. `-4.606cal`C. `2cal`D. `-2cal` |
Answer» Correct Answer - B `K=Ae^(-DeltaH//RT)` `logK=logA-(DeltaH)/(2.303RT)`. `log K=logA-(DeltaH)/(2.303R)xx(1)/(T)`. `log K=[-(DeltaH)/(2.303R)]xx(1)/(T)+logA`. (-DeltaH)/(2.303R)=1`. ltbgt `DeltaH=-2.303R=-4.606cal`. |
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