1.

`vecA` and `vecB` are two vectors gives by `vecA = 2 hati + 3hatj and vecB = hati +hatj`. The magnetiude of the component of `vecA` along `vecB` is :A. `(5)/(sqrt(5))`B. `(3)/(sqrt(2))`C. `(7)/(sqrt(2))`D. `(1)/(sqrt(2))`

Answer» Correct Answer - A
`vecA .vecB = (2hati + 3hatj).((hati + hatj)/(sqrt(2)))`
`=(2+3)/(sqrt(2))=(5)/(sqrt(2))`


Discussion

No Comment Found

Related InterviewSolutions