InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
`veca, vecb and vecc` are three coplanar unit vectors such that `veca + vecb + vecc=0`. If three vectors `vecp, vecq and vecr` are parallel to `veca, vecb and vecc`, respectively, and have integral but different magnitudes, then among the following options, `|vecp +vecq + vecr|` can take a value equal toA. `1`B. `0`C. `sqrt3`D. `2` |
|
Answer» Correct Answer - C::D Let `veca, vecb and vecc` lie in the x-y plane. Let `veca = hati, vecb = -(1)/(2) hati and vecc = -(1)/(2) hati - (sqrt3)/(2)hatj`. Therefore, `|vecp+ vecq + vecr| = |lamda veca + mu vecb + vvecc|` `= | lamda hati + mu(-(1)/(2)hati + (sqrt3)/(2)hatj) + v(-(1)/(2)hati- (sqrt3)/(2)hatj)|` `= |(lamda - (mu)/(2) - (v)/(2))hati + (sqrt3)/(2)(mu - v) hatj|` ` = sqrt((lamda - (mu)/(2) - (v)/(2))^(2) + (3)/(4)(mu-v)^(2))` `= sqrt(lamda^(2)+ mu^(2) + v^(2) -lamda mu -lamda v - mu v)` `" "=(1)/(sqrt2) sqrt((lamda-mu)^(2)+ (mu-v)^(2) +(v-lamda)^(2)) ge (1)/(sqrt2) sqrt(1+1+4) = sqrt3 ` Hence, `|vecp + vecq + vecr|` can take a value equal to `sqrt3` and 2. |
|