1.

Vector vecA is 2 cm long and is 600 above the x-axis in the first quadrant, vector B is 2cm long and is 600 below the x-axis in the fourth quadrant. Find vecA+vecB

Answer»

Solution :
`vecR=vecA+vecB`
`vecR= 2 COS 60^(@) hati+2 sin 60 HATJ+ 2 cos 60 hati-2 sin 60 hatj`
`vecR=4 cos 60 hati=2hati`
`:. 2cm` ALONG x-aixs


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