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Vector vecA is 2 cm long and is 600 above the x-axis in the first quadrant, vector B is 2cm long and is 600 below the x-axis in the fourth quadrant. Find vecA+vecB |
Answer» Solution : `vecR=vecA+vecB` `vecR= 2 COS 60^(@) hati+2 sin 60 HATJ+ 2 cos 60 hati-2 sin 60 hatj` `vecR=4 cos 60 hati=2hati` `:. 2cm` ALONG x-aixs |
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